Aline is parameterized by x=8+6t x = 8 + 6 t and y=3+2t (a) which of the following points are on the section of the line obtained by restricting t to nonnegative numbers (for each, enter y if the point is on the section, and n if not)? (−4,−1): (26 , 9) : (32,11): then, give one more point that is on the section of the line obtained by this restriction: (b) what are the endpoints of the line segment obtained by restricting t to − 5 ≤ t ≤ − 2 ? left endpoint: right endpoint:

We have the line parametrized by

Solving for t in each equation we have that

The point (a,b) lies in the line if when we replace a in the first equation and b in the second equation, the values of t coincide.

a)

1. (-4,-1)

Then, (-4,-1) lies in the line but no lies in the section of the line obtained by restricting t to nonnegative numbers.

2. (26,9)

Since t is positive then (26,9) lies in the line and lies in the section of the line obtained by restricting t to nonnegative numbers.

3. (32,11)

Since t is positive then (32,11) lies in the line and lies in the section of the line obtained by restricting t to nonnegative numbers.

4. If we take t=2 we obtain the point

(20,7) that lies in the section of the line obtained by restricting t to nonnegative numbers.

b)

When t=-5,

correspond to the point (-22,-7).

when t=-2

correspond to the point (-4,-1).

-22<-4 and -7<-1

then the left endpoint (-22,-7) and right endpoint (-4,-1)

do have an equation or graph or

step-by-step explanation:

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant