Let a, b, c be events such that p(a) = 0.2 , p(b) = 0.3, p(c) = 0.4

find the probability that at least one of the events a and b occurs if

(a) a and b are mutually exclusive;
(b) a and b are independent.
find the probability that all of the events a, b, c occur if
(a) a, b, c are independent;
(b) a, b, c are mutually exclusive.

At least  one of the events A and B occurs:

(a) 0.5

(b) 0.44

All of the events A, B, C occur:

(a) 0.024

(b) 0

Step-by-step explanation:

Given:

P(A) = 0.2, P(B) = 0.3, P(C) = 0.4

At least  one of the events A and B occurs:

(a) If A and B are mutually exclusive events, then their intersection is 0.

Probability of at least one of them occurring means either of the two occurs or the union of the two events. Therefore,

(b) If A and B are independent events, then their intersection is equal to the product of their individual probabilities. Therefore,

All of the events A, B, C occur together:

(a) All of the events occurring together means the intersection of all the events.

If A, B, and C are independent events, then their intersection is equal to the product of their individual probabilities. Therefore,

(b) If A, B, and C are mutually exclusive events means events A, B, and C can't happen at the same time. Therefore, their intersection is 0.

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

step-by-step explanation:

idk the answer i want to say 10 but then it would be equal so try 9 but then yeah so yeah we love edgen