Assume that cans of coke are filled so that the actual amounts have a mean of 12.00 oz and a standard deviation of 0.11 oz. find the probability that a single can of coke has at least 12.19 oz.

0.0421

Step-by-step explanation:

Mean(μ) = 12.00 oz

Standard deviation (σ) = 0.11 oz

Z = (x - μ)/σ

Z = (12.19 - 12.00) / 0.11

Z= 0.19/0.11

Z = 1.727

From the normal distribution table, Z = 1.727 = 0.4579

Φ(Z) = 0.4579

Recall that if Z is positive

Pr(x>a) = 0.5 - Φ(Z)

Pr(x > 12.19) = 0.5 - 0.4579

= 0.0421

2 and 1.

step-by-step explanation:

plug in each answer. 0 doesn't work, 1 does. so does 2. 4 doesn't:

0 = 1 is not true.

2 = 2 is true.

4 = 4 is true.

8 = 16 is not true.

hope this !

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: