Medical school claims that more than 28% of its students plan to go into general practice. it is found that among a random sample of 130 of the school's students, 39% of them plan to go into general practice. find the p-value for a test of the school's claim.

0.9974
0.1635
0.3078
0.0026

0.0026

Step-by-step explanation:

Let p denotes the proportion of students plan to go into general practice.

As per given , we have

Alternative hypothesis :

Since the alternative hypothesis is right-tailed so the test is  a right-tailed test.

Also , it is given that ,

i.e. sample size : = 130

x= 490

Test statistic(z) for population proportion :

, where p=population proportion.

= sample proportion

n= sample size.

P-value for right-tailed test = P(z>2.79)=1-P(z≤ 2.79)  [∵P(Z>z)=1-P(Z≤z)]

=1- 0.9974=0.0026  [using z-value table]

Hence, the  P-Value for a test of the school's claim = 0.0026

4 adults and 12 babies

step-by-step explanation:

4 x 7 = 28

12 x 15 = 180

180 + 28 =208

4 x 3 = 12