Will give brainliest if ! given the equation square root of quantity 3x plus 6 end quantity equals 3, solve for x and identify if it is an extraneous solution.

a- 1; solution is extraneous
b- 1; solution is not extraneous
c- 3; solution is extraneous
d- 3; solution is not extraneous

x = 6, solution is not extraneous

Step-by-step explanation:

Given the equation 2 Square root of x minus 5 = 2

. solve for x

Divide by 2 on both sides

Take square on both sides to remove square root

x-5= 1

add 5 on both sides

x= 6

Now we plug in x=6 in our original equation

2 = 2 is true

So x= 6 satisfies our given equation

X=6 is not an extraneous solution

two? xd

step-by-step explanation: