1. a figure has symmetry with respect to a point p if for every point q of the figure a partner point q' exists such that p is the of qq’. 2. a figure has symmetry with respect to a plane x if for every point k of the figure a partner point k' exists such that x is the of kk’. 3. a figure has symmetry with respect to a line m if for every point p of the figure a partner point p' exists such that m is the of pp’.

1. A figure has symmetry with respect to a point P if for every point Q of the figure a partner point Q' exists such that P is the midpoint of QQ’.

2. A figure has symmetry with respect to a plane X if for every point K of the figure a partner point K' exists such that X is the perpendicular bisector of KK’.

3. A figure has symmetry with respect to a line m if for every point P of the figure a partner point P' exists such that m is the perpendicular bisector  of PP’.

Step-by-step explanation

The  following options were missing: perpendicular bisector or midpoint

(-1,0) and (4,0) are x-intercepts.

step-by-step explanation:

x-intercepts are all points on the x-axis.

points (-1,0) and (4,0) are both x -intercepts.

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,