The following data show the scores gina obtained on 12 iq tests:
93, 83, 74, 74, 83, 92, 93, 94, 90, 87, 83, 86
the box plot below represents the data:
box plot has minimum value equal to 74, lower quartile equal to 83, median equal to 86.5, upper quartile equal to 89 and maximum value equal to 94
which of the following is shown incorrectly in the box plot?

the answer is:

upper quartile equal to 89.

we are given a set of values as:

93, 83, 74, 74, 83, 92, 93, 94, 90, 87, 83, 86

on arranging this data in the increasing order or ascending order we get:

74   74     83     83     83     86     87   90   92     93     93     94

the median of the data is the central tendency of the data and it lies in the middle of the data.

so, here median will lie between 86 and 87.

hence the median is:

hence, median is 86.5

the minimum value in the data is 74.

the maximum value of the data is 94.

the upper set of data is:

87   90   92     93     93     94

hence the upper quartile is the median of upper set of data.

so, here the median will lie between 92 and 93.

hence, the median is 92.5.

( since, )

so, the upper quartile is equal to 92.5.

hence, the given statement:

upper quartile equal to 89 is a false statement.

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.

77

step-by-step explanation: