Two volunteer groups plant tress . group a plant the trees in clusters of 3 . group b plant the trees in clusters of 10 . both groups plant the same number of trees . what is the least number of clusters that group b plants ?

  3

Step-by-step explanation:

The least number of trees planted is the least common multiple (LCM) of 3 and 10. Because 3 and 10 have no factors in common, that value is their product, 3·10 = 30.

If group B plants 30 trees, they will have planted 3 clusters.

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )