The scottsdale fire department aims to respond to fire calls in 4 minutes or less, on average. response times are normally distributed with a standard deviation of 1 minute. would a sample of 18 fire calls with a mean response time of 4 minutes 30 seconds provide sufficient evidence to show that the goal is not being met at α = .01?

Let be the population mean.

As per given , we have

Since the alternative hypothesis is right-tailed , so the test is a right-tailed test.

Also, population standard deviation is given , so we perform one-tailed z-test.

Test statistic :

, where = Population mean

= Population standard deviation

n= sample size

= Sample mean

For n= 18 , , , , we have

P-value (for right tailed test): P(z>2.12) = 1-P(z≤ 2.12)  [∵ P(Z>z)=1-P(Z≤z)]\

=1- 0.0340=0.9660

Decision : Since P-value(0.9660) > Significance level (0.01), it means we are failed to reject the null hypothesis.

[We reject null hypothesis if p-value is larger than the significance level . ]

Conclusion : We do not have sufficient evidence to show that the goal is not being met at α = .01 .

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

step-by-step explanation:

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