Mathematics, 05.12.2019 04:31 StevencoolGG
Scores on a certain intelligence test for children between ages 13 and 15 years are approximately normally distributed with μ=106 and σ=15. (a) what proportion of children aged 13 to 15 years old have scores on this test above 92 ? (reminder: proportions are between 0 and 1 - don't put in percentages! )
Answers: 3
and 
.![P(x92)=1-P(x\leq92)\\\\=1-P(\dfrac{x-\mu}{\sigma}\leq\dfrac{92-106}{15})\\\\=1-P(z\leq })\\\\=1-P(z\leq-0.93)=1-(1-P(z\leq0.93))\ \ [\because\ P(Z\leq -z)=1-P(Z\leq z)]\\\\=P(z\leq0.93)=0.8238\ \ [\text{By using z-value table.}]](/tpl/images/0403/9865/bf621.png)
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