15 question



56% of us adults have very little confidence in newspapers. you randomly select 10 us adults. find the probability that the number of us adults who have very little confidence in newspapers is (a) exactly five, (b) at

least six, and (c) less than four

(a) p(5)=

(round to three decimal places as needed)

0.229, 0.530, 0.091

Step-by-step explanation:

given that 56% of US adults have very little confidence in newspapers.

You randomly select 10 US adults.

X, the no of US adults in the sample of 10 adults who have very little confidence in newspapers is

Binomial since there are only two outcomes and each adult is independent of the other

X is bin (10, 0.56)

a) P(X=5) =0.229

b) =0.530

c)

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.