Nov 13, 11: 33: 36 am

jeremiah is blocking off several rooms in a hotel for guests coming to his wedding.

the hotel can reserve small rooms that can hold 3 people, and large rooms that can

hold 4 people. jeremiah reserved twice as many small rooms as large rooms, which

altogether can accommodate 50 guests. determine the number of small rooms

reserved and the number of large rooms reserved.

there were

small rooms reserved and

large rooms reserved.

submit answer

10 small rooms

5 large rooms

Step-by-step explanation:

Let the number of small rooms reserved be s and the number of large rooms reserved be l.

Now what do we know. We know quite well that the small rooms can accommodate 3 guests while the large rooms can accommodate 4 guests. This means the following in equation form:

3s + 4l = 50 (I)

Also we know that she reserved twice as many small rooms as large rooms.

s= 2l(II)

Substitute 2 into 1

3(2l) + 4l = 50

10l = 50

l = 5

Since, s = 2l , this implies s = 2 * 5 = 10

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

12.5 feet

step-by-step explanation: