The orange team was losing by 2 points in the first half of the game. in the second half, the green team scored 5 points, and the orange team did not score.

which expression describes the situation?
(-2) – (-5)

2 + (-5)

2 + 5

(-2) – 5

If you're a player, fan or coach from orange team the expression that describes the situation would be: D. (- 2) - 5.

On the other hand, if you're a player, fan or coach from green team the expression that describes the situation would be: C. 2 + 5.

Step-by-step explanation:

1. Let's review the information provided to answer the question properly:

In the first half of the game = orange team was losing by 2 points

In the second half of the game = green team scored 5 points and the orange team did not score

2.  Which expression describes the situation?

For answering this question, it's important to remark that the answer would be different from orange team's perspective than from green team's perspective.

If you're a player, fan or coach from orange team, this is the expression that describes the situation:

First half = - 2

Second half = - 5

Full game = - 2 - 5

On the other hand, if you're a player, fan or coach from green team, this is the expression that describes the situation:

First half = +2

Second half = +5

Full game = 2 + 5

If you're a player, fan or coach from orange team the expression that describes the situation would be: D. (- 2) - 5.

On the other hand, if you're a player, fan or coach from green team the expression that describes the situation would be: C. 2 + 5.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3