The function, f(x) = –2x2 + x + 5, is in standard form. the quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c = 5. the discriminate b2 – 4ac is 41. now, complete step 5 to solve for the zeros of the quadratic function. 5. solve using the quadratic formula. x = startfraction negative b plus or minus startroot b squared minus 4 a c endroot over 2 a endfraction what are the zeros of the function f(x) = x + 5 – 2x2? x = startfraction negative 1 plus or minus startroot 41 endroot over negative 4 endfraction x = startfraction 1 plus or minus
startroot 41 endroot over negative 4 endfraction x = startfraction negative 1 plus or minus startroot 39 endroot over negative 4 endfraction x = startfraction 1 plus or minus startroot 39 endroot over negative 4 endfraction

the answer is a on edg