Asmall auditorium has 10 rows of seats. there are 12 seats in the row and 16 seats in the second row the number of seats in a row continues to increase by 4 with each additional row. what is the total number of seats in the auditorium?

This problem can be solved through simple arithmetic progression

Let

a1 = the first term of the sequence

a(n) = the nth term of the sequence

n = number of terms

d = common difference

Sn = sum of all terms

given

a1 = 12

a2 = 16

n = 10

d = 16 -12 = 4

@n = 10

a(n) = a1 + (n-1)d

a(10) = 12 + (9)4

a(10) = 48 seats

Sn = (n/2) * (a1 + a(10))

Sn = 5* (12 + 48)

Sn = 300 seats

Therefore the total number of seats is 300.

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer