Detection of radioactive elements. you observe particles emitted from a radioactive sample. your task is to determine whether the sample is composed of an element a or of an element b. it turns out that the emission patterns of these two elements are well approximated by independent poisson processes with parameters (or rates as we say) a and b, respectively. from past data you also know that element a is roughly twice as common as element b. as a result, the number of emitted particles at time t can be modeled by

the camry sales+accord sale=828,000. to make it so the two numbers are 18 thousand apart and still equal 828,000, you first need to find out what half of 828,000 is. 828,000/2=414,000. for the two numbers to equal 828,000, you have to add the same amount as you subtract from the middle. in this case, the number is 9,000 because it's half of 18,000. to equal 828,000, you have to add 9,000 to 414,000 for the camry and subtract 9,000 from 414,000 for the accord. 414,000+9,000=423,000.

414,000-9,000=405,000.

423,000+405,000=828,000.

423,000-405,000=18,

hope it

9 sandwiches per hour

step-by-step explanation:

when we have a rate, we want a 1 in the denominator

27/3 = 9

27 sandwiches/ 3 hours = 9 sandwiches/hour

do you have a picture of the table