Arectangular garden has a walkway around it. the area of the garden is 4(3.5x+1.5). the combined area of the garden and the walkway is 5.5(6x+5). find the area of the walkway around the garden as the sum of two terms. simplified

The area of the walkway is 19x – 32.5

Given that, a rectangular garden has a walkway around it.  

The area of the garden is 4(3.5x+1.5)

The combined area of the garden and the walkway is 5.5(6x+5)

We have to find the area of the walkway around the garden as the sum of two terms.  

Now, we know that,

area of walkway = combined area of garden and walkway – area of garden

So, area of walkway = 5.5(6x + 5) – 4(3.5x + 15)  

Area = 33x + 27.5 – 14x – 60  

Area = 33x – 14x + 27.5 – 60  

Area = 19x – 32.5  

Hence, the area of the walkway is 19x – 32.5

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap

555.99.

step-by-step explanation:

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