[4x -1/
(x+4) (4x² +1)]=
[a\
x+ 4]+
[bx+c\
4x² + 1]
after clearing fractions to decompose, the equation 4x - 1 =a(4x^2+1) + (bx+c)(x + 4) results. if x= -4 what is the value of a?

A = -

Step-by-step explanation:

Given: 4x - 1 = A[4x² + 1] + (Bx + c)(x + 4)

To determine the value of A, we have to eliminate the other two variables, viz, B and C.

To do this simply put x = -4.

We get:

4(-4) - 1 = A[4(-4)² + 1] + 0

⇒ -17 = A(65)

∴ A = is the answer.

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

i can you with this answer

step-by-step explanation: