Find the area of a trapezium whose parallel sides 25cm, 13cm and other sides are 15cm
and 15cm.

The area of Trapezium is 171 cm² .

Step-by-step explanation:

Given as for a trapezium :

The measure of parallel sides are 25 cm and 13 cm

I.e AB = 25 cm  , CD = 13 cm

The measure of other sides of the trapezium = AD = BC = 15 cm

Let The height of measure h is drawn on the side AB

So , The BOC is now a triangle

∴ The measure of BO = AB - AO = 25 cm - 13 cm = 12 cm

Let the area of Trapezium = A

Now, height h =

Or, h =  

Or, h =  

∴  h =  

I.e h = 9 cm

From figure

∵ Area of trapezium = ×Height×( sum of parallel side )

or, A = ×h×( AB + CD )

or , A =  ×9×( 25 + 13 )

Or, A = ×9×38

∴ Area = 171 cm²

Hence The area of Trapezium is 171 cm² . Answer

20%

step-by-step explanation:

to complete this square you have to rotate about the origin 270 degrees clockwise.