Three texas drovers met on a highway and began to dicker as follows:
hank says to jim: "i'll give you six pigs for a horse; then you'll have twice as many critters in your drove as i will have in mine."
duke says to hank: i'll give you fourteen sheep for a horse; then you'll have three times as many critters as i." jim says to duke: i'll give you four cows for a horse; then you'll have six times as many critters as i."
from these interesting facts, can you tell how many animals were in each
of the three droves?

Step-by-step explanation:

Let J, D, and H represent the drove sizes of Jim, Duke, and Hank.

  2(H -6 + 1) = (J +6 -1) . . . . . Hank's offer

  3(D -14 +1) = (H +14 -1) . . . . Duke's offer

  6(J -4 +1) = (D +4 -1) . . . . . . Jim's offer

These equations can be simplified to ...

  2H - J = 15

  3D - H = 52

  6J - D = 21

__

Solution

Adding twice the second equation to the first gives ...

  2(3D -H) +(2H -J) = 2(52) +(15)

  6D -J = 119

Adding 6 times the third equation to this one gives ...

  6(6J -D) +(6D -J) = 6(21) +(119)

  35J = 245

  J = 7

Using this value in the third equation gives ...

  6(7) -D = 21

  42 -21 = D = 21

Using the value of J in the first equation gives ...

  2H -7 = 15

  H = (15 +7)/2 = 11

Then the solution is (J, D, H) = (7, 21, 11).

Jim's drove had 7 animals; Duke's drove had 21 animals; Hank's drove had 11 animals.

the answer will be the last one

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

pls mark as brainliest