If 14 g of a radioactive substance are present initially and 3 years later only 7 g remain, how much of the substance will be present after 4 yr?

5.56 g

Step-by-step explanation:

We are given;

Original mass of radioactive isotope is 14 gMass remaining after 3 years is 7 g But, we know that half life is the time taken by a radioactive isotope to decay to half of its original mass.Therefore, Half life of the radioactive  substance is 3 years.

We need to determine the mass that will be present  after 4 years.

Number of half lives =  4 years ÷ 3 years

                                  = 4/3

Using the formula;

Remaining mass = Original mass × 0.5^n

Therefore;

Remaining mass = 14 g × 0.5^4/3

                            = 5.56 g

Thus, the remaining mass after 4 years will be 5.56 g

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