The area of a rectangle r is 48. if its sides are whole numbers, then its perimeter cannot be

See below

Step-by-step explanation:

If its area is 48, and we know that the area of a rectangle is calculated by:

b*h = area

Where b is the base and h the height, we know that:

b*h = 48

So, b and h are whole numbers such that when multiplied gives as 48. Lets find which whole numbers give us this combination. Lets star with 1 and see if there is a whole number that when multiplied by 1 results in 48, then lets go with 2, then with 3, and so on until 48. Doing so we have:

1*48 = 48

2* 24 = 48

3*16 = 48

4*12= 48

6*8 = 48

Those are the combinations we have.

Now, we know that the perimeter is calculated by the sum of all sides. As in every rectangle we will have two identical pairs, this is, two sides with measure b (base) and two with measure h (height), the perimeter is:

perimeter = b + b + h + h = 2b + 2h

So, lets see for every of the 5 combination its respective perimeter:

1, 48 --> 2*1 + 48*2 = 98

2, 24 --> 2*2 + 2*24 = 52

3, 16  --> 3*2 + 2*16 = 38

4, 12 --> 4*2 + 12*2 = 32

6, 8 --> 6*2 + 8*2 = 28

So, for every combination of sides the perimeters are listed above. Here we see that the perimeter cannot be, for example, an odd number. If your question has options, see if one of these options fits. Do not hesitate in contact if you have any doubt.

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!