Find the work done by f in moving a particle once counterclockwise around the given curve. bold upper f equals (5 x minus 4 y )bold i plus (4 x minus 5 y )bold jf=(5x−4y)i+(4x−5y)j c: the circle (x minus 3 )squared plus (y minus 3 )squared equals 9(x−3)2+(y−3)2=9 what is the work done in one counterclockwise

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles

about 0.75 hours

step-by-step explanation: