Alamina with constant density rho(x, y) = rho occupies the given region. find the moments of inertia ix and iy and the radii of gyration x double bar and y double bar. the part of the disk x2 + y2 ≤ a2 in the first quadrant

Ix = Iy =

Radius of gyration x = y =  

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is . Moment of inertia of quarter disk about its perpendicular is .

Now using perpendicular axis theorem, Ix = Iy = = .

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

what are you doing do you need examples of variable questions?

step-by-step explanation:

5a-1=9               bring the one over the =

5a=10                     divide by your variable

a=2

brainliest? ?

here try this one

3a-24=0