The x7 allele in a species of a plant has 75 percent penetrance for producing red spots and 60 percent penetrance for dwarfism. if these probabilities of penetrance are independent, percent of individuals with the x7 allele will have neither red spots nor will be dwarfs.

10 percent

Step-by-step explanation:

Recall that,

Probability of an event = number of favorable outcome / number of total possible outcome.

and that ;

The percentage penetrance for producing red spots is 75%, hence the probability = 75/100= 0.75

The percentage penetrance for dwarfism is 60%, hence the probability= 60/100= 0.60

let P(A) represent the probability of penetrance for producing red spots = 0.75

let P(B) represent the probability of penetrance for dwarfism = 0.60

Recall that : the probability that an event will occur = 1 - probability that the event will not occur.

let P(A') represent the probability that there will be no red spots= 1- P(A)= 1 - 0.75 = 0.25

let P(B') represent the probability that there will be no dwarf= 1- P(B)= 1 - 0.6 = 0.4

the probability of individuals with X7 allele that will have neither red spots nor will be dwarfs. = P(A') × P(B')= 0.25 × 0.4 = 0.1

In percent the answer will be 0.1 × 100= 10 percent

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

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