Free takes $20 to the arcade and it costs $2 for every game he plays. fred needs to leave the arcade with $5.00 to pay for lunch, what is the most number of games he can play?

Fred can play maximum of 7 games.

Step-by-step explanation:

Money had with Fred = $20

Cost for each game = $2

Fred needs to leave the arcade with $5.00 to pay for lunch.

Money left with Fred  = $20 - $5.00 = $15

Let the number of games be x.

Hence Number of games Fred can play can be calculated as;

Cost for each game multiplied number of games should be less than or equal to Money left with Fred

Hence equation can be framed as;

From above we can say number of games fred can play is 7.5 but number of games cannot be in point hence maximum of 7 games he can play.

Hence Fred can play maximum of 7 games.

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step-by-step explanation:

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