Matteo's schools selling tickets to a christmas musicalon the first day of tickets sales the schools salve 30 adult tickets and 90 children's tickets for a total of $. the school made 670 on the second day by selling 80 adult tickets ad children's tickets, what is the price of one adult ticket and one children's ticket?

The information provided in this question is incomplete. I'm adding some more data to make it solvable and help you with the procedure and results of your own problem

Matteo's schools selling tickets to a Christmas Musical. On the first day of ticket sales the schools sold 30 adult tickets and 90 children's tickets for a total of 330$. The school made 670 on the second day by selling 80 adult tickets and 135 children's tickets, What is the price of one adult ticket and one children's ticket?

Each adult ticket cost $5 each and each children's ticket cost $2

Step-by-step explanation:

System of Linear Equations

When conditions are provided in the form

Where x and y are the unknown variables and a,b,c,d,e,f are known constants , we have a two-variable, two-equations system

Let x=price of one adult's ticket, y=price of one children's ticket

We know that when 30 adult and 90 children attended the Christmas Musical, $330 were made by the school, we also know that when 80 adult and 135 children attended the Christmas Musical, $670 were made by the school. We form this system of equations

To solve the system, we'll use the method of reduction. We first multiply the first equation by -8 and the second by 3

Adding both equations term by term we get

Replacing this value in the first equation we have

x=5

Each adult ticket cost $5 each and each children's ticket cost $2

is means division by fractions

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72