Assuming that the equation defines x and y implicitly as differentiable functions xequals=f(t), yequals=g(t), find the slope of the curve xequals=f(t), yequals=g(t) at the given value of t. x^3+3t^2 =13, 2y^3−3t^2= 42, t=2. the slope of the curve at t=2 is what?

Step-by-step explanation:

Given that x and y are implicitly as differentiable functions.

xequals=f(t), yequals=g(t),

we have to get value of x and y at t =2

we have to find the slope of the curve at t=2

i.e. we have to find

= at t=2

Substitute the values of x and y and also t in these equations to get

Slope =

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: