Abiased coin has a 0.6 chance of coming up heads when flipped. find the probability of flipping 3 or fewer heads in 10 flips. what is the expected number of heads in 10 flips

0.04247,6

Step-by-step explanation:

Given that a biased coin has a 0.6 chance of coming up heads when flipped

X no of coins which showed head is binomial with p = 0.6 since each trial is independent of the other

When there are 10 flips we have n =10

This gives

probability of flipping 3 or fewer heads in 10 flips.

=

Expected number of heads in 10 flips

E(x)

=

this answer is !

none of these

step-by-step explanation:

23 + 34 add up to 57 so just inform the teacher of this really stupid mistake