Afootball quarterback has 2 more chances to throw a touchdown before his team is forced to punt the ball. he misses the receiver on the first throw 30% of the time. when his first throw is incomplete, he misses the receiver on the second throw 10% of the time.

part b: what is the probability of making at least 1 successful throw? (5 points)

i think its a and d

step-by-step explanation:

2425

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

wow ok so the answer is 1k or just k

because of combining like terms xd