Arectangular parking lot has a perimeter of 232 feet. the length of the parking lot is 36 feet less than with. find the length and width

Step-by-step explanation:

So what you need to know is:

1) L= length and W= Width (for this problem)

2) Perimeter: 2(L+W)

3) L = W-36

So 1 and 2 are something you should know. 3 might be difficult in getting. It says that the length is 36 less than the width. This means you have to do subtraction in the problem. If it is 36 less then that means it would something minus 36. Our variable for width is W so it would be W-36.

Next, with the perimeter given and the L=W-36 given, we have to solve the equation.

Substitute L for W in the perimeter equation. 2(L+W)=232 would become 2(W-36+W)=232Divide by 2 on both sides. W-36+W=116. Combine like terms. 2W-36=116Sinplify by adding 36 to both sides. 2W=152Divide by 2 and get W=76Since L=W-36, substitute W=76 for W. L=76-36=40 so L=40. Check to make sure it works (it does based on my math). Your answers are Width equal to 76 units (or whatever unit uaed) and Length equal to 40 units.

The answer is idk yo

Ibelieve the answer is b. y=0 would make the line horizontal across the x.