Write an equation of the line that passes through the given point and is parallel to the given line.

use this equation:

(-5, -2); y= 2/3x + 1

Answer : Equation of line is y=Equation of line is y=x+

Step-by-step explanation:

Theory :

Equation of line is given as y = mx + c.

Where, m is slope and c is y intercepted.

Slope of given line : y = x+1 is m=

We know that line : y = x+1 is parallel to equation of target line.

therefore, slope of target line will be .

we write equation of target line as y= x+c

Now, It is given that target line passes through point ( -5,-2)

hence, point ( -5,-2) satisfy the target line's equation.

we get,

y= x+c

-2= -5+ c

-5= +c

c=

thus, Equation of line is y=Equation of line is y=x+

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: