The top and bottom margins of a poster are 6 ft and the side margins are each 8 ft. if the area of printed material on the poster is fixed at 386 square ft, find the dimensions of the poster with the smallest area.

Dimension

Height =29.01

Breadth=38.70

Step-by-step explanation:

Printed area is =386 and margins as specified.

For printed area let height be x and breadth be y.

x*y=386 ⇒ y =

Now considering the margins

Height = x+6+6=x+12

Weidth = +8 +8= + 16

Area of poster to be minimised =(x+12)( + 16)

Differentiate above area with respect to x and equate to zero to find extrema.

  = 16 -=0

x=17.01

Now plug value of x in height and breadth

 Height =29.01

Breadth=38.70

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)