Flying against the wind an airplane travels 2640 km in 4 hours finder with the wind the same plane travel 7700 km in 7 hours what is the rate of the plane in still air and what is the rate of the pain

Step-by-step explanation:

Let x represent the speed of the plane.

Let y represent the speed of the wind.

Flying Against the Wind an airplane travels 2640 km in 4 hours. This means that the total speed while flying against the wind will be x - y. Speed = distance/time. Therefore

x - y = 2640/4 = 660 - - - - - - -1

Assuming that in still air, the airplane moves in the same direction with the wind. Total speed in still air will be

x + y

Flying with the wind, the same plane travel 7700 km in 7 hours.

Speed = distance/time. Therefore

x + y = 7700/7 = 1100 - - - - - - - 2

Add equation 1 and equation 2. It becomes

2x = 660 + 1100 = 1760

x = 1760/2 = 880

y = 1100 - x

y = 1100 - 880 = 220

The speed of the plane in still air is 880 km/hour

The speed of the wind is 220 km/ hour

Rate of the plane in still air is 1100 km/hour

Rate of the plane against the wind is 880- 220 = 660 km/h

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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