Arectangle has a length of 23 feet less than 10 times it’s width . if the area of the rectangle is 770 square feet find the length

The length of the rectangle is 54 feet .

Step-by-step explanation:

Given as :

The Area of rectangle = 770 square feet

The length is 23 feet less than 10 times its width

I.e Let The length of rectangle = L feet

And The breadth of rectangle = B feet

According to question

Length = 10 times width - 23

Or , L = 10 × B - 23

or, L = 10 B - 23

Now, Since Area of rectangle = A = Length × Breadth

Or, A = L × B

Or, 770 ft² = ( 10 B - 23 ) × B

Or, 770 = 10 B² - 23 B

Or, 10 B² - 23 B - 770 = 0

Now, solving this quadratic equation to get the value of B

Or, B =

or, B =  

Or, B =

Or, B = ,

∴ B = 7.7 , -10

So, The breadth of the rectangle = B = 7.7 feet

So, The length of the rectangle = L = ( 10 × 7.7 - 23 )

I.e L = 54 feet

Hence The length of the rectangle is 54 feet . Answer

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.