Between 2005 and 2010
,
the average rate of inflation was about 4.3
%
per year. if a cart of groceries cost $160

in 2005, what did it cost in 2010
?
a cart of groceries cost approximately nothing

in 2010
.

A cart of groceries that costed US$ 160 in 2005, costs US$ 197.49 in 2010 at an average rate of 4.3% of inflation.

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Cost of cart of groceries in 2005 = US$ 160

Period of inflation analysis = 5 years

Inflation average rate = 4.3 % compounded annually

2. Let's find the future value of the cost of a cart of groceries in 2010, using the following formula:

FV = PV * (1 + i) ⁿ

PV = Cost of cart of groceries in 2005 = US$ 160

number of periods (n) = 5 (Period of inflation analysis = 5 years)

Inflation average rate (i) = 4.3% = 0.043

Replacing with the real values, we have:

FV = 160 * (1 + 0.043) ⁵

FV = 160 * (1.043) ⁵

FV = 160 * 1.234302311

FV = 197.49 (Rounding to two decimal places)

Note : Same answer to question 14111742 answered by me.

answer: median

step-by-step explanation:

the median is the middle value when a data set is ordered from least to greatest

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584