What are the solution(s) to the quadratic equation 50 - x2 = 0?
x = +275
x = +63
x = +575
no real solution

x = ± 5

Step-by-step explanation:

Given

50 - x² = 0 ( add x² to both sides )

x² = 50 ( take the square root of both sides )

x = ± = ± = ± 5

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c