Find the values of x and y : ek= 7x+5, kg= 3x+17, hk= 3y-11, kf= y+5
need answer asap

Step-by-step explanation:

We know:

The diagonals of the parallelogram are divided in half.

Therefore

EK ≅ KG and HK ≅ KF.

We have

EK = 7x + 5, KG = 3x + 17, HK = 3y - 11 and KF = y + 5

Equations:

(1)   7x + 5 = 3x + 17

(2) 3y - 11 = y + 5

Solutions:

(1)

7x + 5 = 3x + 17       subtract 5 from both sides

7x + 5 - 5 = 3x + 17 - 5

7x = 3x + 12       subtract 3x from both sides

7x - 3x = 3x - 3x + 12

4x = 12           divide both sides by 4

4x/4 = 12/4

x = 3

(2)

3y - 11 = y + 5                add 11 to both sides

3y - 11 + 11 = y + 5 + 11

3y = y + 16         subtract y from both sides

3y - y = y - y + 16

2y = 16           divide both sides by 2

2y/2 = 16/2

y = 8

i will pick c put check it over to be sure

step-by-step explanation: