During winter months freshwater fish sense the water getting colder and swim 7/8 of the depth of a 32 foot deep lake how many feet did the fish swim?

28 FT

Step-by-step explanation:

The freshwater fish swam 28 feet

Step-by-step explanation:

Hi, to answer this we simply have to multiply total depth of the lake (32) by the fraction that the freshwater fish swam (7/8).

Mathematically speaking:

32 x (7/8) = 224/8 =28 feet  

So, in conclusion, the freshwater fish swam 28 feet  

Feel free to ask for more if needed or if you did not understand something.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

answer: 8d

step-by-step explanation:

45+5= 50+5=55+5=60