At a college bookstore, carla purchased a math textbook and a novel that cost a total of $54,not including tax. if the price of the math textbook ,m, is $8 more than 3 times the price of the novel, n, which system of linear equations could be used to determine the price of each book?

The price of novel is$ 11.5  

The price of math textbook $ 42.5

Step-by-step explanation:

Given as :

The total cost of the Math textbook and novel = $54

The price of the math textbook = $ m

The price of the novel = $ n

And, The price of the math textbook  is $8 more than 3 times the price of the novel .

According to question

The price of math textbook = 3 times the price of novel + $ 8

Or, $ m = 3 × $ n + $ 8

I.e m = 3 n + 8                  ...........A

And

The total cost of the Math textbook and novel = The price of the math textbook + The price of the novel

Or,  $ m + $ n = $ 54

I.e m + n = 54                      ..........B

Solving equation A and B

So, putting the value of m from A to eq B

Or , ( 3 n + 8 ) + n = 54

Or, 3 n + n + 8 = 54

Or, 4 n = 54 - 8

or, 4 n = 46

∴ n =

I.e n = = $ 11.5

So, The price of novel = n = $ 11.5

Again, put the value of n in Eq B

So, m = 54 - n

I.e m = 54 - 11.5

∴  m = $ 42.5

So, The price of math textbook = m = $ 42.5

Hence , The price of novel is$ 11.5  And The price of math textbook $ 42.5 Answer

it’s supposed to be -4+45=41

step-by-step explanation: