Problem 11-18 (modified). nasa scientists obtained the followingdata from airborne radiometer scans using the estar method ofaperature synthesis. soil moisture percentages: 19,16,15,16.5,15,14source: d. m. levine, a. j. griffis, c. t. swift, and t. j. jackson, "estar: a synthetic aperature microwave radiometer forremote sensing applications," proceedings of the ieee, december 1994, p. 1795.these data represent sample measurements taken over the 220-240degree k brightness temperature range. the theoretical model statesthat the mean volumetric soil moisture percentage should be 13.5%.use the confidence interval approach to conclude whether the sampledata support or refute the null hypothesis that the mean estarmeasurements equal the theoretical level, using a .05 level ofsignificance. lower 95% confidence limit = 1.upper 95% confidence limit = 2.

95% confidence interval is 15.92±1.67. Since lower confidence limit 14.25% is higher than the theoretical level 13.5%, we can reject the null hypothesis that the mean ESTAR measurements equal the theoretical level, at 0.05 significance.

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

margin of error (ME) from the mean can be calculated using the formula

ME= where

Mean of the sample is= ≈ 15.92

Standard deviation of the sample is ≈1.59

two tailed t value of 95% confidence level in 5 degrees of freedom is 2.571

Then ME= ≈ 1.67

95% confidence interval is then 15.92±1.67

Lower 95% confidence limit =14.25%

Upper 95% confidence limit= 17.59%

the answer is: the length is 5/6 yards.

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step-by-step explanation:

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58