Find the 4th term of the geometric sequence when a1=31 and common ratio, r = 4. round your answer to 2 decimal places, if needed.

1984

Step-by-step explanation:

The formula for the general term of a geometric sequence is given by the formula:

Where

a_1 is the first term

r is the common ratio

n is the number of term (nth term)

For this problem, we have to find the 4th term, so n = 4.

Also, given the first term (a_1) is 31

and, common ratio (r) is 4

We substitute and find:

Hence,

The 4th term of this sequence is "1984"

t = 3

step-by-step explanation:

put t = 3 in this expression :

(3²-1)(3²-2)(3² - 3)(3² - 4) = 8×7×6×5 = 56×30 = 1680