3. consider the expressions sq root of 15, sq root of 97 and sq root of 40 locate the approximate value of each on a number line.
then, estimate each square root to the nearest tenth.

Square root of 15

√ 15 = 3.9 (Rounding to the nearest tenth)

Square root of 97

√97 = 9.9 (Rounding to the nearest tenth)

Square root of 40

√40 = 6.3 (Rounding to the nearest tenth)

Step-by-step explanation:

Square root of 15

√ 15 = 3.9 (Rounding to the nearest tenth)

Square root of 97

√97 = 9.9 (Rounding to the nearest tenth)

Square root of 40

√40 = 6.3 (Rounding to the nearest tenth)

Location on a number line

√ 15, between + 3 and + 4, very close to +4

√40, between + 6 and + 7, close to +6

√97, between + 9 and + 10, very close to +10

one that is bigger than 3 1/2

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !