Aplane flies from atlanta to new york to los angeles angainst the wind in 5 hr the return trip back to atlanta with the wind only 4 hr if the diatance between atlanta and los angeles is 3200 km find the speed of the plane in still air and the speed of the wind

speed of plane is 720 km/h

Speed of wind is 80km/h

Step-by-step explanation:

Let x represent the speed of the plane.

Let y represent the speed of the wind.

The plane flies from Atlanta to los Angeles and against the wind in 5hrs and the distance between Atlanta and los Angeles is 3200 km.

Since it flew against the wind, the speed would be x-y km/hour

Distance = speed × time. Therefore

3200 = 5(x - y )

3200 = 5x - 5y - - - - - - - - - 1

the return trip back to Atlanta with the wind only 4 hr. This means that the speed is x+y km/hour. Therefore

3200 = 4(x+y)

3200 = 4x + 4y - - - - - - - - 2

Multiplying equation 1 by 4 and equation 2 by 5, it becomes

12800 = 20x - 20y

16000 = 20x - 20y

Adding both equations, it becomes

28800 = 40x

x = 28800/40 = 720

Substituting x = 720 into 3200 = 5(x - y )

x - y = 3200/5 = 640

y = 720 - 640 = 80

your answer is the frist one

hop i