Now you'll evaluate the integral ∫c7ycos(6x)dx+2xydy on the closed curve c consisting of the line segments from (0,0) to (5,7) to (0,7) to (0,0) using green's theorem. green's theorem says this integral can be rewritten in the form ∫∫df(x, y)da in this integral, f(x, y) = (7/6)ysin(6x) setting up the double integral over the region d, you get

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step-by-step explanation:

the true ones are a b and d

answer: -10

step-by-step explanation:

s(t) = 1 - 10t

s(x) = 1 - 10x

s(x + h) = 1 - 10(x + h)

            = 1 - 10x - 10h

s(x + h) - s(x) = 1 - 10x - 10h - (1 - 10x)

                      = 1 - 10x - 10h - 1 + 10x

                      = -10h

= -10