The owner of a computer repair shop has determined that their daily revenue has mean $7200 and standard deviation$1200. the daily revenue totals for the next 30 days will be monitored. what is the probability that the mean daily revenuefor the next 30 days will exceed $7500

The probability that the mean daily revenue for the next 30 days will exceed $7500 is 0.0855

Step-by-step explanation:

It has been given that

Now, the formula for z-score of a normal distribution is given by

Substituting the known values, we get

Simplifying, we get

Now, we have to find that the daily revenue for next 30 days will exceed $7500.

Thus, we have to find

P(z>1.369238)

From the normal distribution table, we have

P(z>1.369238)= 0.0855

Therefore, required probability is 0.0855

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.