The sum of three numbers is 45. the second of the three numbers is three more than twice the first number, x. the third number is two more than the first number, x. which equation can be used to solve for the first number, x?

a. x+x+x=45

b. x+(x+3)+(x+2)=131

c. x(2x+3)+(x+2)=45

d. x+(2x+3)+x=45

Let's say that the first number is x
the second is y
and the third is z

we start off with the equation that the sum of the three number is 45


the "second of the three numbers is three more than twice the first number" means that


the "third number is two more than the first number" means that


we plug and back into the first first equation and get


assuming you are missing an addition sign in your option C
your answer would be C. x+(2x+3)+(x+2)=45