At a college bookstore, kyle purchased a textbook and a calculator that cost a total of $94, not including tax. the price of the textbook, t, is $10 less than 3 times the price of the calculator, c. based on these cost, what was the cost of the textbook? a) $21 b) $26 c) $68 d) $78

Step-by-step explanation:

Let the price of the calculator = $x

Therefore, the price of the texbook

= $(3x - 10). Since the prices of t & c =

$94, it implies that,

$(3x - 10) + $x = $94

Solving this together, you have

3x - 10 + x = 94

4x = 94 + 10,

4x = 104

dividing both side by the coefficient of x which is 4, = $26

There fore, calculator price is $26 .

The price of the textbook = $94 - $26

= $68. Answer is C

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8