Salaries of 40 college graduates who took a statistics course in college have a mean of $62, 200. assuming a standard deviation of $11,766 construct a 90% confidence interval for estimating the population mean.

round to the nearest integer as needed.

Step-by-step explanation:

We want to determine a 90% confidence interval for the mean salaries of college graduates

Number of sample, n = 40

Mean, u = $62, 200

Standard deviation, s = $11,766

For a confidence level of 90%, the corresponding z value is 1.645. This is determined from the normal distribution table.

We will apply the formula

Confidence interval

= mean +/- z ×standard deviation/√n

It becomes

62200 +/- 1.645 × 11766/√40

= 62200 +/- 1.645 × 1860.4

= 62200 +/- 3060.358

The lower end of the confidence interval is 62200 - 3060.358 =59139.642

The upper end of the confidence interval is 62200 + 3060.358 =65260.358

Therefore, with 90% confidence interval, the mean mean salaries of college graduates is between $59139.642 and $65260.358

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

rx and sx

step-by-step explanation: