What is the equation for a line that passes through the points (8,2) and (-7,2)

y = 0x + 2

Step-by-step explanation:

Find the slope.

Slope = y2 - y1

              x2 - x1

Plug in the points.

Slope =    2 - 2         =   0

                -7 - 8            -15

Pick a point to plug into the y = mx + b formula

I picked (8,2)

Now plug in the point and slope.

(Your teacher might prefer you to use 0/-17, but it can be simplified to 0, so I'll just use that.)

Equation: (2) = 0(8) + b

                 2  = 0 + b

                 2 = b  (b = 2)

Now put your slope and the y-intercept into the equation, and it will be:

y = 0x + 2

It's a bit hard to show on keyboard, so I hope you understand.

the answer is 0052

0 0 5 2

5 0 2 6 3 5

− 0

2 6

− 0

2 6 3

− 2 5 0

1 3 5

− 1 0 0

3 5

1.m=2

2.m=-6

3.m=3

4.m=1/2

glad to